give me answer fast.........
Attachments:
Answers
Answered by
0
given: angle A=30°
Angle B=45°
tan 30°=DC/AC
=3/AC
1/√3=3/AC
:. AC=3√3
tan 45°=DC/CB
1=3/CB
:.CB=3
AB= AC + CB
= 3√3+3
=3(√3+1)
Angle B=45°
tan 30°=DC/AC
=3/AC
1/√3=3/AC
:. AC=3√3
tan 45°=DC/CB
1=3/CB
:.CB=3
AB= AC + CB
= 3√3+3
=3(√3+1)
Attachments:
Similar questions