Question

Give me answer fast I will mark as Brainlist
1 :Find additive inverse of
i) -93
ii) 396
iii) -3125
iv) 0
2:Evaluate [75+(-60)]+[(-25)+(-11)]4
3:Fill with correct integer
i)9-___=11
ii)-14+___=4
iii)-1+___=9
iv)7+(-7)=___
4:Arrange in ascending order
que)13/28,7/10,1/5,3/7
Ans)_____________??
5:Find the sum
i)⅔,+¾,4/5
ii)1½+2⅓

Answer 1

1) 93
2)396
3)3125
4)0
2
1)-84
3
1)-2
2)18
3)10
4)0
4
1/5,3/7,13/28,7/10
5) 1)221/100
2)23/6

Answer 2

Step-by-step explanation:

1. Additive inverse of the given numbers:

i) -93  = 93

ii) 396  = -396

iii) -3125  = 3125

iv) 0 = 0

2. [75+(-60)]+[(-25)+(-11)]4

= (75 -60) +(-25 -11)4

= 15 + (-36)4

= 15 - 144 = -129

3. i) 9- (-2) = 11

ii) -14 + 18 = 4

iii) -1 + 10 = 9

iv)7 + (-7) = 0

4. We have to arrange 13/28, 7/10, 1/5, 3/7 in ascending order

$\dfrac {13}{28}, \dfrac {7}{10}, \dfrac 15, \dfrac 37\\\\lcm\ of\ denominatior(28, 10, 5, 7) = 140$

Now multiply by 140 in given numbers

$\dfrac {13}{28} \times 140, \dfrac {7}{10}\times140, \dfrac 15\times 140, \dfrac 37\times 140\\\\65, 98, 28, 60$

Ascending order: 28, 60, 65, 98.

5. we have to find the sum of the given numbers

$i) \dfrac 23+ \dfrac 34+ \dfrac 45 = \dfrac {40 + 20 + 48}{60} = \dfrac {133}{60}\\\\ii) 1 \dfrac12 + 2\dfrac13 = \dfrac 32 +\dfrac 73 = \dfrac {9+14} 6 = \dfrac{23}6$