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In triangle ADB and trin. ABC ,
we have ,
Ang A= Ang A ( common)
and Ang D = Ang B =90
so, ADB IS SIMILAR TO ABC
HENCE, 2=1 proved.
we have ,
Ang A= Ang A ( common)
and Ang D = Ang B =90
so, ADB IS SIMILAR TO ABC
HENCE, 2=1 proved.
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