Question

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Answer 1

Answer:

Let the number be x

(3x²- 4y²+5xy+20)- x= -x²-y²+6xy+ 20

x= -x²-y²+6xy+20-3x²+ 4y²-5xy- 20

-x= -4x²-3y²+xy

x= 4x²+ 3y²- xy

Hope it Helps

Answer 2

Solution:

We will be using the concept of addition and subtraction of algebraic expressions to solve the given question.

Let us assume the missing part as X.

Therefore according to the question,

(3x2 - 4y2 + 5xy + 20) - (X) = - x2 - y2 + 6xy + 20

Let us shift the terms to find the value of X

X = 3x2 - 4y2 + 5xy + 20 - (- x2 - y2 + 6xy + 20)

X = 3x2 - 4y2 + 5xy + 20 + x2 + y2 - 6xy - 20

X = 4x2 - 3y2 - xy

Thus, the expression that should be subtracted is 4x2 - 3y2 - xy.

Step-by-step explanation:

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