Question

give me answer in Pages​

Answer 1

Answer:

the action or process of moving or being moved.

"the laws of planetary motion"

Answer 2

Answer:

Given:-

A horse and two cows together cost ₹680. If a horse cost ₹80 more than a cow, find the cost of each.

To Find:-

The cost of a horse and two cows.

Note:-

●》Here, we will find cost of a horse and two cows by A horse cost + Two cow's cost = Together cost ( by taking some value of two cow and a horse )

●》For finding unknown value, known value needs to transposed from its side to another and signs are also ( signs are not changed in multiple and divisional value ). For example - Positive becomes Negative, Multiple becomes Divisional.

Solution:-

$\huge\red{Cost \ \ of \ \ horse \ \ and \ \ cow = ?}$

$\huge\red{Let \ \ cow's \ \ cost \ \ be \ \ "x"}$

$\huge\red{So, Two \ \ cow's \ \ cost = x + x}$

$\huge\red{According \ \ to \ \ question, Horse \ \ cost = x + ₹80}$

☆ According to note first point~

▪︎$A \ \ horse \ \ cost + Two \ \ cow's \ \ cost = Together \ \ cost$

▪︎$x + ₹80 + x + x = ₹680$

▪︎$3x + ₹80 = ₹680$

☆ According to note second point ( transposing )~

▪︎$3x = ₹680 - ₹80$

▪︎$3x = ₹600$

▪︎$x = \dfrac{₹600}{3}$

☆ After dividing~

▪︎$x = ₹200$

$\huge\pink{Horse \ \ cost = x + 80 = ₹200 + ₹80 => ₹280}$

$\huge\pink{Two \ \ cow's \ \ cost = x + x = ₹200 + ₹200 => ₹400}$

Checking:-

♤ Let's check that sum of horse cost and two cow's cost gives together cost or not.

• $A \ \ horse \ \ cost + Two \ \ cow's \ \ cost = Together \ \ cost \implies ?$

• $₹280 + ₹400 = ₹680 \implies ?$

• $₹680 = ₹680 \implies ✔$

$\huge\green{Hence, Proved : Horse \ \ cost = ₹280}$

$\huge\green{\ \ \ \ \ \ \ \ \ \ \ Two \ \ cow's \ \ cost = ₹400}$

Answer:-

Hence, The horse cost = ₹280

Two cow's cost = ₹400

:)