Question

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Answer 1

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Answer 2

AB=60 m;DF=77 m;AD=25m; BF=26mwe calculate the CF:

CF=DF-CD=77-60=17 m

For ABCF, we calculate the perimeter of triangle

P=BC+BF+CF=25+26+17=68 m

we calculate the semiperimeter of the triangle:

p=P/2=68/2=34 m we use the formula of Heron:

At=vpx(p-BC)x(p-BF)x(p-CF); = 34(34-25)(34-26)(34-17) =v34*9*8*17=141616= 204 m2 we calculate the height of triangle:

BE=2At:CF=(2x204):17=408:17=24 m

we calculate the area of Trapezium

A =[(AB+DF) BE):2=[(60+77)x24=(137x24)2=3288:

2=1644 m2