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In the given figure
AB = 13cm
CD = 7cm
BC = 10cm
CL = ?
BCL is a right angled triangle
For finding height we will use Pythagoras theorem
LB = 13cm-7cm
=6cm
BC = 10cm
CL = ?
H²=P²+B²
(BC)²=(CL)²+(LB)²
(10)²=(CL)²+(6)²
100=(CL)²+36
100-36=(CL)²
64=(CL)²
8²=(CL)²
8cm=CL
Area of trapezium = 1/2×(b1+b2)×Height
=1/2×(7+13)×8cm²
=20×4cm²
=80cm²
Hope it helps!!
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