Question

give me answer of my question

Answer 1

bst of lk fr ur exam

Answer 2

Hi!☺
Here.........

Radius = 3.5cm
OD = 2cm.

Area of quadrant = 1/4 × πr^2

= 1/4 × 22/7 × (3.5)^2

= 1/4 × 22/7 × 12.25

= 1/4 × 22 × 1.75

= 5.5×1.75

= 9.625sq.cm
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So , area of quadrant = 9.625 sq.cm
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Radius = 3.5 cm

Thus ,
OA = OB = 3.5 cm
OD = 2cm .............................(given)

A(∆BOD) = 1/2 × base × height
A(∆BOD) = 1/2 × OB × OD
A(∆BOD) = 1/2 × 3.5 × 2
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A(∆BOD) = 3.5 sq.cm.
__________________
Now,
Area of shaded region =
Area of quadrant - Area of ∆BOD
= 9.625 - 3.5
=6.125 sq .cm .
_____________________________
Final Answer:
Therefore, the area of shaded region
is 6.125 sq .cm.
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◆Hope this Helps◆