Math, asked by singghaditya0, 3 days ago

give me answer of this question ​

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Answered by BharniAce
4

Answer:

Step-by-step explanation:

<ACB = <CAD (Alternate interior angles)

<CAD = 50

<AOD = 90 (The angle of the bisector of a rhombus in 90)

In triangle AOD,

      <OAD + <AOD + <ADO = 180(Angle sun of a triangle)

       50 + 90 + <ADO = 180

        <ADO = 180 - (50+90)

        <ADO = 180 - 140

        <ADO = 40

Therefore, m<ADO = 40

Hope, this helps you

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Answered by Avistudytime
0

Answer:

The angle ADB=40degree

Step-by-step explanation:

As we know, the sum of all the angles in a Rhombus is 360 degree

Now angle ACB=50 degree so the angle ACD will also be 50 degree

As the opposite angles of a Rhombus are equal so, 100+100=200 degree

∴ 360-200=160 degree

Now, 160÷2=80

So angle ADC is 80 degree

Now in order to find the angle ADB we have to divide 80 from 2

The answer is 40 degree

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