Math, asked by dmoolya2005, 5 months ago

give me answer please

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Answered by kritikasinha83823

3

$pr ^{2} = pq ^{2} + qr^{2}$

The above relation is derived by taking side PR as hypotenuse PQ as perpendicular and QR as the base of triangle PQR

Answered by ruchiiishah12

1

Step-by-step explanation:

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