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hey mate here is your answer
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please mark me as a brainliest
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Here u should know sin 60 which is √3/2
Let's find cos 60
As sin^2 60 + cos^2 60 = 1
cos 60 = √ 1 - sin^2 60 = √ 1- 3/4 = 1/2
As tan 60 = sin 60/cos60 = √3
So tan 60/ sin 60 + cos 60
= √3)/ √3/2 + 1/2
= √3)/ ( √3+1)/2
= 2√3)/ √3 + 1
Multiply N ans D by √3 -1
2√3( √3 -1)/ (√3 +1)(√3 -1)
6 - 2√3)/ 2
2( 3 -√3)/ 2
3 -√3
√3( √3 -1)
Let's find cos 60
As sin^2 60 + cos^2 60 = 1
cos 60 = √ 1 - sin^2 60 = √ 1- 3/4 = 1/2
As tan 60 = sin 60/cos60 = √3
So tan 60/ sin 60 + cos 60
= √3)/ √3/2 + 1/2
= √3)/ ( √3+1)/2
= 2√3)/ √3 + 1
Multiply N ans D by √3 -1
2√3( √3 -1)/ (√3 +1)(√3 -1)
6 - 2√3)/ 2
2( 3 -√3)/ 2
3 -√3
√3( √3 -1)
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