Question

give me answer please... (any. two )​

Answer 1

Answer:

iv .5sec θ - 12cosec θ = 0

5sec θ = 12cosec θ

5/cos θ = 12/sin θ

sin θ/cos θ = 12/5

Therefore, Tan θ = 12/5

iii.

The given points are A(1,2),B(1,6),C(1+23,4)

Using distance formula,

AB=(1−1)2+(6−2)2=42=4

BC=(1+23−1)2+(4+6)2=12+4=4

CA=(1−1−23)2+(2−4)2=12+4=4 

Since AB=BC=CA

∴ABC is an equilateral triangle  

I hope this is helpful please mark me brilliant I am new here