give me answer please..... fast........
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Step-by-step explanation:
Step-by-step explanation
465 = n(n + 1)/2
\begin{gathered}930 = n^{2} + n\\\end{gathered}
930=n
2
+n
n^{2} + n - 930n
2
+n−930 = 0
n^{2} + 31n - 30n - 930 = 0n
2
+31n−30n−930=0
n( n + 31) - 30(n + 31) = 0n(n+31)−30(n+31)=0
(n +31)(n-30) = 0(n+31)(n−30)=0
Therefore n = 30n=30 or (-31)
But number of terms cannot be negative so (-31) is not possible
So n = 30
So 30 consecutive natural numbers should be added to get 45.
I HOPE IT HELPS
2part
Let one number be x. other number = (50-x)
x^2=(50-x)^2 = 2050
x^2+2500-100x+x^2 = 2050
2x^2-100x+2500-2050=0
2x2-100x+450=0
x^2-50x+225=0 225=5*5*3*3
(x-5)(x-450=0 225=5*45
x=5 or 45
smaller number = 5
larger number =45
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