Question

give me answer please

Q-12,13,14​

Answer 1

(a) When Barium chloride solution is added to an aqueous solution of sodium sulphite, we obtain a white precipitate of Barium Sulphite along with Sodium Chloride.

 BaCl2 + Na2SO3=BaSO3 + 2NaCl

(b) This precipitation reaction can also be categorised as a double displacement reaction.

(c) The white precipitate of sodium chloride reacts with hydrochloric acid to form Barium Chloride and water and release sulphur dioxide. Barium chloride is a soluble salt which is why the white precipitate of Barium Sulphite disappears. The chemical reaction for the above process is

BaCI3 + SO2 + H2O