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Q-12,13,14
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(a) When Barium chloride solution is added to an aqueous solution of sodium sulphite, we obtain a white precipitate of Barium Sulphite along with Sodium Chloride.
BaCl2 + Na2SO3=BaSO3 + 2NaCl
(b) This precipitation reaction can also be categorised as a double displacement reaction.
(c) The white precipitate of sodium chloride reacts with hydrochloric acid to form Barium Chloride and water and release sulphur dioxide. Barium chloride is a soluble salt which is why the white precipitate of Barium Sulphite disappears. The chemical reaction for the above process is
BaCI3 + SO2 + H2O
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