Question

Give me answer quick​

Answer 1

$\frac{ \sqrt{2 } - 1}{ \sqrt{2} + 1 }$

$= \frac{( \sqrt{2} - 1)( \sqrt{2} - 1) }{ (\sqrt{2} + 1)( \sqrt{2} - 1)}$

$= \frac{ {( \sqrt{2} - 1) }^{2} }{ {( \sqrt{2)} }^{2} - ( {1)}^{2} }$

$= \frac{2 - 2 \sqrt{2} + 1 }{2 - 1}$

here I use identity (a-b)^2=a^2-2ab+b^2 in upper part

$= \frac{3 - 2 \sqrt{2} }{1}$

$= 3 - 2 \sqrt{2}$

#### I hope so you like my answer ####