Question

give me answer this question​

Answer 1

Step-by-step explanation:

In ΔPBC and ΔQCB

PB=QC [AB=AC and P and Q are midooints]

angle PBC= angle QCB [ angle opp. to equal side

is equal]

BC=BC [ common]

Hence ΔPBC is congruent to ΔQCB

thus CP=BQ (by cpct)