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Work performed by A in one day = 1/15
Work performed by B in one day = 1/12
Work performed by C in one day = 1/20
(Since all of them work together for two days before C leaves)
Work done by A, B, C together in 2 days = 2*(1/15+1/12+1/20) = 2/5
Work left after 2 days = 1 - 2/5 = 3/5
(Now A & B together have to complete 3/5th of total work)
Let’s assume A & B together complete work in “x” days.
Then,
3/5 = x*(1/15+1/12)
3/5 = x*9/60
By solving we get
x = 4 days, hence, A & Bhave to work for another 4 days.
Work performed by B in one day = 1/12
Work performed by C in one day = 1/20
(Since all of them work together for two days before C leaves)
Work done by A, B, C together in 2 days = 2*(1/15+1/12+1/20) = 2/5
Work left after 2 days = 1 - 2/5 = 3/5
(Now A & B together have to complete 3/5th of total work)
Let’s assume A & B together complete work in “x” days.
Then,
3/5 = x*(1/15+1/12)
3/5 = x*9/60
By solving we get
x = 4 days, hence, A & Bhave to work for another 4 days.
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