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The answer is angle APC is 55
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SOLUTION:-
Given,
∠ABC= 30°
∠ACD=110°
By exterior angle theorem:
∠ACD=∠A +∠B
110°=∠A+ 30°
∠A= 110°-30°
∠A= 80°
∠ACD +∠ACP= 180° (Linear pair)
110° + ∠ACP= 180°
∠ACP= 180° -110°
∠ACP= 70°
In ∆APC,
∠APC +∠PAC+ ∠ACP= 180°
∠APC+ 1/2∠A +70°= 180°
∠APC+ 1/2×80°+70°= 180°
∠APC+ 40° + 70° = 180°
∠APC= 180° - 110°
∠APC= 70°
Hope it helps ☺️
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