Math, asked by shaliniaswal125, 10 days ago

give me correct answer
points Kai liyai faltu answer mathe dena please​

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Answers

Answered by XxkrishnadeewanixX
2

Answer:

the correct answer is

 \sqrt[266 \frac{15}{?} ]{?}

789^2..

Answered by Aryan0123
9

Step-by-step explanation:

Given Quadratic Equation → √6x² - 4x - 2√6 = 0

When questions that cannot be easily factorized by splitting the middle term are given, then go for factorizing it by using Quadratic Formula.

\bf{x = \dfrac{-b \pm \sqrt{b^{2}-4ac} }{2a}}\\\\

Compare this with the general form of Quadratic Equation i.e. ax² + bx + c = 0.

We observe that:

  • a = √6
  • b = -4
  • c = -2√6

\\

Substitute these values in the formula.

\leadsto \: \sf{x = \dfrac{4\pm \sqrt{(-4)^{2}-4(\sqrt{6})(-2\sqrt{6})}}{2\sqrt{6}}}\\\\

\implies \sf{x = \dfrac{4 \pm \sqrt{16+48} }{2\sqrt{6}}}\\\\

\implies \sf{x = \dfrac{4 \pm \sqrt{64} }{2 \sqrt{6}}}\\\\

\implies \sf{x = \dfrac{4 \pm 8 }{2 \sqrt{6}}}\\\\

Taking positive sign,

\sf{x = \dfrac{12}{2\sqrt{6}}=\dfrac{6}{\sqrt{6}}=\sqrt{6}}\\\\

\\

Taking negative sign,

\sf{x = \dfrac{-4}{2\sqrt{6}}=-\dfrac{\sqrt{6}}{3}=-\sqrt{\dfrac{2}{3}}}\\\\

\therefore \: \boxed{\boldsymbol{x=\sqrt{6} \: \: or \: \: -\sqrt{\dfrac{2}{3}}}}\\\\

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