Question

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♥️⭐ If Q( 0,1) is equidistant from P(5,-3) and R(x,6) , find the values of x .Also find the distance QR and PR. !please solve the que​ ⭐♥️

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Answer 1

Explanation:

PQ = √[(5-0)^2 + (-3-1)^2]

= √ [ 25 + 16]

=√ (41) units

RQ = √[(x -0)^2 + (6-1)^2]

= √[ x^2 +25]

RQ = PQ

41 = x^2 +25

x= -4

or

x =4

for x = -4 and x = 4

RQ = √41 units

PR =√[(4-0)^2 + (6-1)^2]

= √[ 16 + 25]

= √(41)

Hope it helps u

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