Question

Give me formula for
(x+1/x)^2=?

Answer 1

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@Reema

Answer 2

We can derive this simply by the Identity

(a + b)²


We know that (a + b)² = a² + b² + 2ab


So simply putting it as

$(x + \frac{1}{x} ) {}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \times x \times \frac{1}{x}$
=>
$(x + \frac{1}{x} ) {}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2$

So this is the outcome.


You have to just remember the formula of
(a + b)² = a² + b² + 2ab

In case it is ( x - 1/x) then apply

(a - b)² = a² + b² - 2ab

Therefore
$(x - \frac{1}{x}) {}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2$
hope it helps dear friend ☺️✌️