give me gibbis free energy in above question
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ΔG=ΔG₀+RTlnQ
given,
ΔG₀ = -24.8kJ/mol
Q=P₍CH₃OH₎/(P²₍H₂₎P₍CO₎)=2/(2²*4)=1/8
ΔG = -24800+ 8.314 × (273+25) × ln0.125 = -29951.9661393
= -29.952 kJ/mol
given,
ΔG₀ = -24.8kJ/mol
Q=P₍CH₃OH₎/(P²₍H₂₎P₍CO₎)=2/(2²*4)=1/8
ΔG = -24800+ 8.314 × (273+25) × ln0.125 = -29951.9661393
= -29.952 kJ/mol
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