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In ∆ABD and ∆ACD
AD=AD. (common)
AB=AC. (given)
angle C = angle B. (angle opposite to equal sides are equal)
therefore ∆ABD ≈∆ACD
So, BD=CD. (by cpct)
angle BAD = angle CAD. (by cpct)
hence proved
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here is your proper answer..
please mark it as brainliest plz plz...
Hope it will help you...
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