Math, asked by anjalisingh2006, 7 months ago

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Answered by nishitakishore
1

Answer:

I. \frac{\sqrt{10} + \sqrt{15} }{\sqrt{2} }

= \frac{\sqrt{10} + \sqrt{15} }{\sqrt{2} }  ×  \frac{\sqrt{2} }{\sqrt{2} }

= \frac{\sqrt{20} + \sqrt{30}  }{2}

= \frac{2\sqrt{5}  + \sqrt{30} }{2}

II. \frac{\sqrt{3} + 1 }{\sqrt{2} - \sqrt{3} }

Rationalizing factor = \sqrt{2} + \sqrt{3}

\frac{\sqrt{3} + 1 }{\sqrt{2} - \sqrt{3} }   ×   \frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} + \sqrt{3}}

= \frac{\sqrt{6} + 3 + \sqrt{2}  + \sqrt{3 } }{\sqrt{2}^{2}  + \sqrt{3} ^{2}  }

= \frac{\sqrt{6} + 3 + \sqrt{2}  + \sqrt{3 } }{2-3 }

= \frac{\sqrt{6} + 3 + \sqrt{2}  + \sqrt{3 } }{-1 }

- ({\sqrt{6} + 3 + \sqrt{2}  + \sqrt{3 } })

= -{\sqrt{6} - 3 - \sqrt{2}  - \sqrt{3 } }

Answered by Juveri08
0

Answer:

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