Question

give me right answer​

Answer 1

Step-by-step explanation:

4x-5y+16=0

2x+y-6=0

${by/: elimination ~method}$

$(4x-5y+16=0 )×1 \\ \\(2x+y-6=0)×2$

$4x-5y+16=0 \\-4x-2y+12=0$

$-7y+28 \\ -7y=-28 \\ y = /frac{-28}{-7}$

${y=4}$

Answer 2

Answer:

x=1 and y= 4

Step-by-step explanation:

4x-5y+16=0 (i)

2x+y-6 =0 (ii)

From eq:(i)

2x+y-6=0

For x it gives

x= (6-y)/2

Or

x= 3- y/2 (iii)

Put eq(iii) in eq (i)

4x-5y+16=0

4(3-y/2)-5y+16=0

After solving

12-2y-5y+16=0

-7y+28=0

-7y= - 28

Y= - 28/-7

Or

Y=4

now, put y=4 in eq(iii)

x= 3-y/2

x=3-4/2

x= 3-2

Or

x =1

:- Solution set is

{x = 1, y = 4}

Hope it helps you

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