give me solution of this question
Attachments:

Answers
Answered by
0
Answer:
option (3) is correct.
MnO4- is reduced and SO3^-2 is oxidised.
Explanation:
MnO4- is reduced because oxidation number of Mn is changed from +7 to +2.
Oxidation number is decreased .
Then, MnO4- is reduced.
SO3^-2 is oxidised because oxidation number of S is changed from +4 to +6.
Oxidation number is increased .
Then, SO3^-2 is oxidised.
Oxidation number
The degree of oxidation of an atom or ion or molecule, for simple atoms or ions the the oxidation number is equal to the ionic charge.
Attachments:

Similar questions