give me solution of this question
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Took me some while to do it on paper
Hope it really helps!
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⭐⭐Here is your answer⭐⭐
Given that :- AB = 39 m , BC = 25 m and AC = 56 m
Area of ∆,
S= 39+25+56/2 = 120/2 = 60 m
= √s(s-a)(s-b)(s-c)
= √60(60-39)(60-25)(60-56)
= √ 60 x 21 x 35 x 4
= √176400
= 420 m²
Now,
Area of quadrilateral= 2 x Area of ∆.
Area of Quadrilateral=( 2 x 420) m² = 840 m²
Rate of spreading mud =RS (840 x 100)
= Rs. 84000
⭐⭐Be Brainly⭐⭐
Given that :- AB = 39 m , BC = 25 m and AC = 56 m
Area of ∆,
S= 39+25+56/2 = 120/2 = 60 m
= √s(s-a)(s-b)(s-c)
= √60(60-39)(60-25)(60-56)
= √ 60 x 21 x 35 x 4
= √176400
= 420 m²
Now,
Area of quadrilateral= 2 x Area of ∆.
Area of Quadrilateral=( 2 x 420) m² = 840 m²
Rate of spreading mud =RS (840 x 100)
= Rs. 84000
⭐⭐Be Brainly⭐⭐
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