Question

give me solution please

Answer 1

⭐⭐Here is your answer⭐⭐

Given:- AB= 3cm , BC = 4cm , CD= 6cm, DA= 5cm and diagonal, AC= 5cm.

Area of ∆ ABC
S is the half perimeter


S= 3+4+5 /2
S= 12/2 = 6cm


= √S(s-a)(s-b)(s-c)
= √6(6-3)(6-4)(6-5) cm²
= √6x3x2x1 cm²
= √36 cm²

= 6 cm²

Now, Area of ∆ ADC,

S= 5+6+5/2
S= 16/2 = 8cm

= √s(s-a)(s-b)(s-c)
= √8(8-5)(8-6)(8-5)
= √8x3x2x3
= √144 cm²
= 12 cm²

Now Area of Quadrilateral= Area of ∆ ABC + Area of ∆ ADC

Area of Quadrilateral= (6+12) cm²

Hence, Area of Quadrilateral= 18cm²

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Answer 2

Step-by-step explanation:

ANSWER EXPLANATION: According to the original information given, the estimated average number of shoppers in the original store at any time (N) is 45. In the question, it states that, in the new store, the manager estimates that an average of 90 shoppers per hour (60 minutes) enter the store, which is equivalent to 1.5 shoppers per minute (r). The manager also estimates that each shopper stays in the store for an average of 12 minutes (T). Thus, by Little’s law, there are, on average, N=rT=(1.5)(12)=18 shoppers in the new store at any time. This is

45−18

45

=60

percent less than the average number of shoppers in the original store at any time.

The final answer is 60