Math, asked by GrabMe, 11 months ago

Give me some formulas for inverse trigonometry ​


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Answers

Answered by TheInsaneGirl
7

Here goes the answer -

{ {{\bold{Inverse \: Trigonometry :}}}}

Here are some basic formulas

 |1.|  \:  \: sin {}^{ - 1} x + cos \:  {}^{ - 1} x =  \frac{\pi}{2}  \\  \\  |2.|  \:  \: sec {}^{ - 1} x + tan\:  {}^{ - 1} x =  \frac{\pi}{2}  \\    \\  |3.|  \:  \: cosec{}^{ - 1} x + cot \:  {}^{ - 1} x =  \frac{\pi}{2}  \\  \\

Then we have the identity function

tan {}^{ - 1} x \:  +  tan {}^{ - 1} y =  \: tan {}^{ - 1} ( \frac{x + y}{1 - xy} )

 tan {}^{ - 1} 2x =  \: 2 \: tan {}^{ - 1} ( \frac{2x}{1 - x {}^{2} } )

Note - These are the most frequently used ones with reference to class 12. Especially remember the formulas for Tangents.

{ {{\bold {Thanks}}}}

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Answered by rahman786khalilu
5

Answer:

most frequently used If you want I can give u more

hope it helps

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