Question

give me the answer .


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Answer 1

As we know in regular hexagon, interior angles are 120

So A = B= C= D= E= F= 120

NOW area of one sector = pie r^2/360 × 120

= pie R^2/3

So area of 6 sectors = 6 × pie r^2/3

= 2 pie r^2


27)In OAC and OCD

D is point on circle where normal and tangent making 90 ( I forgot to write there)

A = D= 90

OC = OC

OA = OD

SO SAS

SO OAC ~ OCD

SO <ACO = <OCD = theta/2

IN OAC

sin theta/2 = OA/OC = a/OC

OC = a/sin theta/2


in OBC

sin ¶( its phie I am taking as O) = OB/OC

sin¶ = OB/a/sin theta/2

sin¶ = OB sin theta/2)/ a

a sin¶ = OB sin theta/2

OB = a sin¶ / sin theta/2

= a sin¶ cosec theta/2

Answer 2

Answer:

Step-by-step explanation:

Hope it helps you... This is 25 no. S answer...