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Answer:
Let the two numbers be x and y
x+y=40
y=40-x
x+(40-x)=40
x-y=4
y=x-4
x-(x-4)=4
So, required ratio is 11:9
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Question
The sum of two numbers be 40 and their difference is 4.what is the ratio of the two numbers ?
Given
sum of two numbers is 40 and difference is 4.
To Find
Ratio of the two numbers
Solution
step by step explanation
We don't know the numbers so ,we have to assume the numbers.
Let us assum that the two numbers be x and y
according to the question:-
x+y=40--(1)
x-y=4----(2)
Now ,add both Equation
x+y+x-y=40+4
=>2x=44
=>x=22
X=22
Put X's value in Equation 1
x+y=40
=>22+y=40
=>y=40-22
=>y=18
y=18
We have to find the ratio of two numbers
Ratio =22/18=11/9
(c)Ratio is 11:9
Check
Sum of two numbers be 40=>22+18=40
Difference of numbers be 4=>22-18=4
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