Question

give me the answer I will mark you asbrilliant​

Answer 1

Answer:

< QAP = < BAC = 25°

By exterior angle theorem,

< ACD = < BAC + < ABC

100° = 35° + < ABC

< ABC = 100° - 35°

< ABC = 65°

< BCA + < ACD = 180° [ Linear Pair]

< BCA + 100° = 180°

< BCA = 80°

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Answer 2

Answer:

Hello friend !!

angle ACB = 80° , angle BAC= 35° , angleABC=65°

find out angle ACB by linear pair with angle ACD and angle BAC with vertically opposite angle with angle QAP and angle ABC by angle sum property .

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