Math, asked by rishita84, 1 year ago

give me the answer of question number 9,10,11,12,13

Attachments:

Answers

Answered by aaravshrivastwa
4
⭐⭐Here is your answer⭐⭐


9).=> (5/3)^-4 x (5/3)^-5 = (5/3)^3x

Hence base is equal,
=> -4 +(-5) = 3x
=> -(4+5) = 3x
=> -9 = 3x
=> -9/3 = x
=> -3 = x
or
=> x = -3

10). => (4/9)⁴ x (4/9)^-7 = (4/9)^2x-1

Hence base is equal,

=> 4 +(-7) = 2x-1
=> 4-7+1 = 2x
=> -3+1 = 2x
=> -2 = 2x
=> -2/2 = x
=> -1 = x
or
=> x = -1

11). => Let the no. be y

=> y x (-6)^-1 = 9^-1
=> y x (-1/6)¹ =( 1/9)¹
=> y = 1/9 x 6/1
=> y = 2/3

12). => Let the no. be p

=> p ÷ (-2/3)^-3 = (4/27)^-2
=> p ÷ (-3/2)³ = (27/4)²
=> p ÷ (-27/8) = (729/16)
=> p = 729/16 x 8/27
=> p = 27/2

13). => 5^2x+1 ÷ 25 = 125

=> 5 ^2x+1 ÷ (5)² = (5)³
=> 5 ^2x+1 x (1/5)² = 5³
=> 5^2x+1 x (5)^-2 = 5³
Hence base is equal

=> 2x+1-2 = 3
=> 2x-2 = 3
=> 2x = 3+2
=> 2x = 5
=> x = 5/2


⭐⭐Be Brainly⭐⭐

aaravshrivastwa: Okay
aaravshrivastwa: Follow me
rishita84: I followed you now
rishita84: just now
rishita84: see
aaravshrivastwa: ohk
rishita84: bye
aaravshrivastwa: bye
aaravshrivastwa: see u with your new question
rishita84: ok
Answered by gautamkumarjha1430
0

Answer:

Step-by-step explanation:

Similar questions