Question

Give me the answer of second part please

Answer 1

5YY6KfK5hpJCnS4kIXUfG3443WXCy3K0Pvd7fjyXDpyQqTAyeFcESXkPxfqw/BBZ

Answer 2

Answer:

$( \frac{7}{9})^{2} + ( \frac{9}{7}) {}^{ - 2} \\ we \: have \: t \: opposite \: \\ fraction \: to \: make \: posite \: power \\ ( \frac{7}{9} ) {}^{2} + ( \frac{7}{9} ) {}^{2} \\( \frac{7}{9} + \frac{7}{9} ) {}^{2} \\ ( \frac{7 + 7}{9} ) {}^{2} \\ ( \frac{14}{9} ) {}^{2} \\ \frac{196}{81}$

your next second question is

$if \: x = (\frac{5}{3} ) {}^{2} \times ( \frac{3}{5}) {}^{ - 3} find \: the \: value \: of \: {x}^{ - 2} \\ at \: first \: \\ \\ we \: have \: to \: convert \: \\ negative \: power \: in \: to \: positive \\ x = ( \frac{5}{3}) {}^{2} \times ( \frac{5}{3} ) {}^{3} \\ x = ( \frac{5}{3}) {}^{2 + 3} \\ x = ( \frac{5}{3}) {}^{5} \\ so \: value \: of \: {x}^{ - 2} \\ = ( \frac{5}{3} ) {5}^{-2} \\ = ( \frac{5}{3} ) {}^{ - 10} or = > ( \frac{3}{5} ) {}^{10} \\ i \: hope \: it \: will \: be \: \\ helpful \: so \: please \: mark \: me \: brainlist$ and last question is attached in photos