Question

give me the answer of this question​

Answer 1

$\huge{\sf{\red{Given}}}$$\begin{cases}\longrightarrow P(6, 6) \\\longrightarrow Q(4, 4) \\\longrightarrow R(-1, -1) \end{cases}$

$\huge\bf{\red{\overbrace{\underbrace{\purple{To\:\:Find:}}}}}$

★Plot these points on 'Cartesian Plane ' and check whether these points are co-linear.

$\huge\bf{\red {\overbrace{\underbrace{\purple{Concept\:\:Used:}}}}}$

★For checking colinearity we will use distance formula.

$\huge\bf{\red {\overbrace{\underbrace{\purple{Answer:}}}}}$

Distance formula is

$\large\red{\boxed{\purple{\sf{AB=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2}}}}}}$

Where

Coordinate of A is $(x_{1}, y_{1})$

Coordinate of B is $(x_{2}, y_{2})$

_____________________________________

Distance between PQ,

$\implies PQ =\sqrt{(6-4) ^{2}+(6-4) ^{2}}$

$\implies PQ =\sqrt{2^{2}+2^{2}}$

$\implies PQ =\sqrt{4+4}$

$\implies PQ =\sqrt{8}$

${\underline{\boxed{\red{.\degree.PQ=2\sqrt{2}}}}}$

______________________________________

Distance between QR,

$\implies QR =\sqrt{[4-(-1)]^{2}+[4-(-1)]^{2}}$

$\implies QR =\sqrt{(4+1)^{2}+(4+1)^{2}}$

$\implies QR =\sqrt{5^{2}+5^{2}}$

${\underline{\boxed{\purple{.°. QR = 5\sqrt{2}}}}}$

______________________________________

Distance between PR,

$\implies PR = \sqrt{[6-(-1)]^{2}+[6-(-1)]^{2}}$

$\implies PR =\sqrt{(7)^{2}+7^{2}}$

$\implies PR =\sqrt{49+49}$

${\underline{\boxed{\orange{.°. PR = 7\sqrt{2}}}}}$

______________________________________

We have

PQ=2√2

QR=5√2

PR=7√2.

It is clear that,

PQ+QR=PR

Therefore points P, Q & R are co-linear.

Answer 2

Step-by-step explanation:

$hope \: it \: will \: help \: u$