Question

give me the answer of this question and write full answer do not write the half answer ​

Answer 1

Step-by-step explanation:

7)

Let, one angle be 3x and another be 2x

We know,

Opposite angles of parallelogram are equal,

Hence, third angle = 3x and fourth angle = 2x

Now,

Since the sum of angles of a parallelogram is 360 degrees

3x + 2x + 3x + 2x = 360 degrees

10x = 360 degrees

x = 36 degrees

Similarly,

1st angle = 3*36 degrees = 108 degrees

2nd angle = 2*36 degrees = 72 degrees

3rd angle = 3*36 degrees = 108 degrees

4th angle = 2*36 degrees = 72 degrees

8)

Since all the angles of a rhombus are equal.

angle P = angle Q = angle S = angle R = 126 degree

and diagonals of rhombus vertex angles

Hence, angle R = angle QRP + angle PRS

                          = 63 degrees

Again,

The opposite side of rhombus are parallel,

Hence, angle SPR = angle QRP (Alternate angles)

             z = 63 degrees

Now,

In triangle POS, (Let the point where PR and QS are intersected be O)

z + x + 90 degrees = 180 degrees (Since, the sum of angles of a triangle is 180 degrees)

63 degrees + x = 180 degrees

x = 117 degrees

Again,

x + y = angle Q (Since, the opposite angles of rhombus are equal)

117 degrees + y = 126 degrees

y = 54 degrees

                             

                       

Answer 2

Answer:

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