Question

give me the answer

question no.5 and 7

Answer 1

4.Lateral surface area of cubical box of edge 10cm = 4×102 cm2 = 400 cm2

Lateral surface area of cuboid box = 2(l+b)×h   = 2×(12.5+10)×8
= 360 cm2

Thus, lateral surface area of the cubical box is greater by (400 – 360) cm2 = 40cm2

2)Total surface area of cubical box of edge 10 cm =6×102cm2=600cm2

Total surface area of cuboidal box = 2(lb + bh + lh)

= 2(12.5×10 + 10×8 + 8×12.5)
 = 610 cm2

Thus, total surface area of cubical box is smaller by 10 cm2




7.Dimension of bigger box = 25 cm × 20 cm × 5 cm

Total surface area of bigger box = 2(lb + bh + lh)
   = 2(25×20 + 20×5 + 25×5)
  = 1450cm2

Dimension of smaller box = 15 cm × 12 cm × 5 cm

Total surface area of smaller box = 2(lb + bh + lh)
= 2(15×12 + 12×5 + 15×5)
= 630cm2

Total surface area of 250 boxes of each type = 250(1450 + 630)                                             =250×2080 cm2 = 520000 cm2
Extra area required = 5/100(1450 + 630) × 250 cm2 = 26000 cm2

Total Cardboard required = 520000 + 26000 cm2 = 546000 cm2

Total cost of cardboard sheet = ₹(546000 × 4)/1000 = ₹ 2184