Give me the answer quickly guys
PLSSSSSS
Attachments:
Answers
Answered by
1
in the identity
(a+b+c)³=(a³+b³+c³)+3(a+b)(b+c)(c+a)
(a+b+c)³-(a³+b³+c³)= 3(a+b)(b+c)(c+a)
(a+b+c)³-a³-b³-c³= 3(a+b)(b+c)(c+a)
Hence proved
please mark it as brainiest answer
(a+b+c)³=(a³+b³+c³)+3(a+b)(b+c)(c+a)
(a+b+c)³-(a³+b³+c³)= 3(a+b)(b+c)(c+a)
(a+b+c)³-a³-b³-c³= 3(a+b)(b+c)(c+a)
Hence proved
please mark it as brainiest answer
sciencemathsharsh:
please mark it as brailiest
Similar questions