Question

give me the answer quickly of question 6​

Answer 1

Answer:

These are alternate angles so that AB || CD

Step-by-step explanation:

Let draw BM ⊥ PQ and CN ⊥ RS.

Given that  PQ || RS so that  BM || CN

Use the property of Alternate interior angles

∠2 = ∠3          … (1)

∠ABC = ∠1 +  ∠2

But ∠1 =  ∠2 so that

∠ABC = ∠2 +  ∠2

∠ABC = 2∠2

Similarly

∠BCD = ∠3 +  ∠4

But ∠3 =  ∠4 so that

∠ BCD = ∠3 +  ∠3

∠ BCD = 2∠3

From equation first

∠ABC = ∠DCB

These are alternate angles so that AB || CD

Hence proved

Answer 2

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