Question

GIVE ME THE ANSWERRRRRR​

Answer 1

Answer:

your answer is $\frac{6}{9}$ $ab^{2}$

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HOPE IT HELPS YOU!! have a great day ahead!!!

Answer 2

EVALUTION★

GIVAN★

$= a {}^{2} + 4b {}^{2} + \frac{c {}^{2} }{9} + 4ab - \frac{4bc}{3} - \frac{2ca}{3}$

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this written as

$= a {}^{2} + (2b) {}^{2} + ( - \frac{c}{3}) {}^{2} + 2(a)(2b) + 2(2b)( - \frac{c}{3} ) + 2( - \frac{c}{3} )(a)$

we know that

$= > (a + b + c) {}^{2} = a {}^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ca$

comparision

• $= > a = a \\ \\ = > b = 2b \\ \\ = > c = \frac{ - c}{3}$

to

$(a + 2b + ( - \frac{c}{3} ) ){}^{2}$

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I hope it helps you