Question

give me the correct answer

step by step​

Answer 1

Step-by-step explanation:

7. let p(x) = x^2 -3

zero of the polynomial is the value of x where p(x) is 0

putting p(x) = 0

x^2 -3= 0

x^2 - (√3)^2 = 0

using a^2-b^2 = (a+b) (a-b)

(x-√3) ( x+√3) = 0

so, x= -√3, √3

so zeroes of p(x) are -√3, √3

8. For a cubic polynomial maximum number of zeroes are three .

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