Question

Give me the solution of given question in image of maths ​

Answer 1

From the question , we have

length of the side of the tank (a) =1.5 m =150 cm

Now, area of the tank covered by the tiles = 4a^2 +a^2 ( excluding base)

= 5a^2

= 5(150)^2 cm ^2

= 5×150×150 cm^2

No of tiles required to covered the tank = 5×150×150/25×25 = 180.

No . of dozens in 180 = 180/12 = 15

Since, cost of one dozen = Rs.360

→ Cost of 15 dozens = 15 ×Rs. 360

= Rs.5400

Answer 2

From the question , we have

length of the side of the tank (a) =1.5 m =150 cm

Now, area of the tank covered by the tiles = 4a^2 +a^2 ( excluding base)

= 5a^2

= 5(150)^2 cm ^2

= 5×150×150 cm^2

No of tiles required to covered the tank = 5×150×150/25×25 = 180.

No . of dozens in 180 = 180/12 = 15

Since, cost of one dozen = Rs.360

→ Cost of 15 dozens = 15 ×Rs. 360

= Rs.5400