Give me the solution of this question plz
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I think this is the answer.
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given equation is
x^2-2(5+2k)x +3(7+10k)=0
now, it is given that roots are equal
therefore, D=0
so, b^2-4ac=0
2(5+2k)^2 - 4*1*3(7+10k)=0
100+16k^2+80k-84 - 120k=0
16k^2-40k + 16 =0
4k^2-10k +4=0. (dividing by 4)
4k^2-8k -2k +4=0
4k(k-2)-2(k-2)=0
(k-2)(4k - 2)=0
k = 2,1/2
x^2-2(5+2k)x +3(7+10k)=0
now, it is given that roots are equal
therefore, D=0
so, b^2-4ac=0
2(5+2k)^2 - 4*1*3(7+10k)=0
100+16k^2+80k-84 - 120k=0
16k^2-40k + 16 =0
4k^2-10k +4=0. (dividing by 4)
4k^2-8k -2k +4=0
4k(k-2)-2(k-2)=0
(k-2)(4k - 2)=0
k = 2,1/2
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