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Step-by-step explanation:
(i) Let angle ABC and angle ACB be y
So, by angle sum property of triangles:
y+y+50 =360
2y+50=360
2y=360-50
2y=310
y=310/2
y=155 _________equation 1
Now, angle ACB + angle ACD =180 (Linear pair of angles)
y+x=180
155+x=180 (from equation 1)
x=180-155
x=25°
(ii) Here,PR=RS
therefore,PRS is an isosceles triangle
So,RSP=RPS=30°
therefore angle P= angle RPS+angle RPQ
30°+52°= 82°
Now by ASP of triangle:
angle P+angleQ+angles=360°
82°+ x +30=360°
112°+x =360°
So, x=360-112
x= 248°
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