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Solution is that
A+b+c=0
(A+b+c)^3=(0)^3
=0
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AL is perpendicular to DC
By pythagoras theorem,
(AL)^2 + (DL)^2 = (AD)^2
4^2 + (DL)^2 = 5^2
16 + (DL)^2 = 25
(DL)^2 = 25 - 16
(DL)^2 = 9
DL = 3cm
Similarly,
MC=3cm
AB=LM
(AL is perpendicular to DC,
Angle ALM = 90°
Hence,ABLM is a square)
LM= 7 cm
Length of DC= MC + LM + DL
= 3+7+3
=13cm
Area of Trapezium =1/2(a+b)h
=1/2(7+13)4
=1/2 x 20 x 4
=1/2 x 80
=40 sq. cm
HOPE IT HELPS!!!♥️♥️
By pythagoras theorem,
(AL)^2 + (DL)^2 = (AD)^2
4^2 + (DL)^2 = 5^2
16 + (DL)^2 = 25
(DL)^2 = 25 - 16
(DL)^2 = 9
DL = 3cm
Similarly,
MC=3cm
AB=LM
(AL is perpendicular to DC,
Angle ALM = 90°
Hence,ABLM is a square)
LM= 7 cm
Length of DC= MC + LM + DL
= 3+7+3
=13cm
Area of Trapezium =1/2(a+b)h
=1/2(7+13)4
=1/2 x 20 x 4
=1/2 x 80
=40 sq. cm
HOPE IT HELPS!!!♥️♥️
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