Question

give me your correct answer​

Answer 1

Answer:

Angle BAC = Angle EAF (Vertically Opposite Angles)

Angle BAC = 45°

Angle ACB + Angle ACD = 180° (Linear Pair)

Angle ACB + 105° = 180°

Angle ACB = 180° – 105°

Angle ACB = 75°

Angle BAC + Angle ABC = Angle ACD (Exterior Angle Property)

45° + Angle ABC = 105°

Angle ABC = 105° – 45°

Angle ABC = 60°

All the angle of ∆ABC are 45°, 75° and 60°.

Answer 2

Answer:

the angle of ∆ABC are 45°,75°and 60°

Step-by-step explanation:

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