Question

give one example of quadratic equation that has real solution. solve to explain

Answer 1

Answer:

We have taken

3x^2-3√3x+4=0 which gives us equal roots

Answer 2

Answer:

5x2 + 6x + 1 (The discriminant method)

Step-by-step explanation:

Comparing the above eqn. with ax2 + bx + c

a=5, b=6, c=1

d (∆) = b2 - 4ac

= (6)2 - 4 (5)(1)

= 36 - 20

= 16 ---------- (I)

x = -b +- √b2 - 4ac

____________

2a

= -(6) +- √16 ------[ from (I) ]

________

2(5)

= -6 +- 4

______

10

now,

x = -6 +4 or x = -6 -4

_____ _____

10 10

x = -1 or x = -1

__ __

5 1