Chemistry, asked by Amayra1440, 5 months ago

Give one observation:

a) Zinc nitrate is strongly heated .

b) Copper carbonate is strongly

heated.

c) Sulphur dioxide is passed

through acidified potassium permanganate solution.

d) HCl vapours combine

with ammonia gas.​

Answers

Answered by RaviKumarNaharwal
0

Explanation:

a) When zinc nitrate crystals are strongly heated, zinc oxide white residue and brown vapors of nitrogen dioxide gas are formed.

b) When copper carbonate{CuCO3} is heated it decomposes forming copper oxide {CuO} and carbon dioxide {CO2}. This is a decomposition reaction. Brisk effervescence of CO2 gas is released while heating.

c) Sulphur dioxide (SO2) is passed through an acidified solution of potassium permagnate (KMnO4) which is purple in colour.On doing so, sulphur dioxide being a strong reducing agent ,reduces the purple coloured solution to form a colourless solution .

2KMnO4+5SO2+2H2O→K2SO4+2MnSO4+2H2SO4 (purple) (colourless)

d) Ammonia is a weak base and it combines with HCl to form ammonium chloride. But moisture is necessary to bring out this reaction. So when exposed to air they combine to form dense fumes of ammonium chloride. The salts produced by the action of ammonia on acids are known as the ammonium salts and all contain the ammonium ion.

Answered by Anonymous
2

your qution and ans byby

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