Question

give one pair of values of X and Y such that p(x,y) is equidistant from the point A (-1,8) and B(3,4)
​​

Answer 1

Answer: x-y+5=0

Step-by-step explanation:

√(x+1)^2+(y-8)^2=√(x-3)^2+(y-4)^2

squaring both the sides:-

x^2+1+2x+y^2+64-16y=x^2+9-6x+y^2+16-8y

2x-16y+65=(-6x)+25-8y

2x+6x-16y+8y+65-25=0

8x-8y+40=0

x-y+5=0

Answer 2

Answer:

Step-by-step explanation:

Step-by-step explanation:

√(x+1)^2+(y-8)^2=√(x-3)^2+(y-4)^2

squaring both the sides:-

x^2+1+2x+y^2+64-16y=x^2+9-6x+y^2+16-8y

2x-16y+65=(-6x)+25-8y

2x+6x-16y+8y+65-25=0

8x-8y+40=0

x-y+5=0