Question

Give ONE value of b that will cause 4x^2 + bx + 25 = 0 to have one real solution.
PLEASE ACTUALLY HELP ME I NEED IT

Answer 1

Answer:

First fact, quadratic equation has only one real solution. It means equation has real and equal roots.

So, Discriminant = 0.

${b}^{2} - 4ac = 0 \\ {b}^{2} - 4 \times 4 \times 25 = 0 \\ {b}^{2} - 400 = 0 \\ {b}^{2} = 400 \\ = > b = 20 \: or \: - 20.$

Answer 2

Answer:

this is correct....................